Give an inequality showing the range of vertex angle measures in an isosceles triangle where the congruent sides are longer than the base of the triangle?

In an equilateral triangle the sides are all congruent and the vertex angle id 60 degrees.
Therefore in the case of the congruent sides being greater than the base the vertex angle will be greater than 60 degrees and less than 180 degrees.
So the inequality is:-

60 > x < 180    where x is the vertex angle.