Mark estimates that the distance from his house to his school is 15.5 mi. the actual distance is 14.5 mi. to the nearest tenth of a percent, what is the percent error in mark's estimate?

The percentage error of the estimate is 6.9%

The data values are given as:

Actual = 14.5 miles

Estimate = 15.5 miles

The percentage error in the estimate is then calculated as:

So, we have:

Evaluate

Hence, the percentage error of the estimate is 6.9%

Read more about percentage error at:

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answer: city needs 2.4 inches of rainfall more to match the record of 40 inches.

step-by-step explanation:

since we have given that

total annual rainfall a city record = 40 inches

this year, total rainfall recorded = 37.6 inches

number of inches of rainfall   is needed to match the record of 40 inches is given by

hence, city needs 2.4 inches of rainfall more to match the record of 40 inches.

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )