Write the equation of a line that passes through (-4,15) and (-7,10) in point slope form

(-4,15),(-7,10)
slope = (10 - 15) / (-7 - (-4) = -5 / (-7 + 4) = -5 / -3 = 5/3

there can be 2 answers to this...depending on the point u use...
y - y1 = m(x - x1)
slope(m) = 5/3
using point (-4,15)...x1 = -4 and y1 = 15
now we sub
y - 15 = 5/3(x - (-4)..not done yet
y - 15 = 5/3(x + 4) <=== this is one answer

y - y1 = m(x - x1)
slope(m) = 5/3
using point (-7,10)x1 = -7 and y1 = 10
now we sub
y - 10 = 5/3(x - (-7)...not done yet
y - 10 = 5/3(x + 7) <=== and here is the other answer

First subtract 10 from both side
y^2+6y-16=0
(y+8)(y-2)=0
-8 and 2