What is an equation for the linear function whose graph contains the points (2, 5) and (3, 0) ?

x + 5y - 15 = 0

Step-by-step explanation:

First, we find the slope

Given : x₁ = 2 y₁= 5 x₂= 3 y₂=0

m = y₂ - y₁ / x₂ - x₁

m = 0-5 / 3-2

m = -5 / 1 = -5

equation of a straight line;

y - y₁ = m (x - x₁)

y - 5 = -5(x - 2)

y - 5 = -5x + 10

y + 5x - 15 = 0

12

step-by-step explanation:

12 + 5 = 17

12x2=24

24-7=17

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9