Mathematics, 24.07.2019 15:40 haileycrane

Simon wanted to find the equation of a line that passes through (–6, 5) and is perpendicular to the graph of 3x + 2y = –11. his work is shown below. 1. 3x + 2y = –11 written in slope-intercept form is y = -3/2x - 11/2 , so the slope is -3/2. 2. the slope of the perpendicular line is -2/3. 3. substitute the point and the new slope into point-slope form to get y – 5 = -2/3(x – (– 4. simplifying, the line is y – 5 = -2/3(x + 6). is simon’s work correct? a. no, the slope of the line 3x + 2y = –11 is not . b. no, the slope of the line perpendicular to the line 3x + 2y = –11 should be . c. no, he did not substitute the point and the slope into point-slope form correctly. d. yes, the work is correct.

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Simon wanted to find the equation of a line that passes through (–6, 5) and is perpendicular to the...