Simplify 8 over the quantity of 2 plus 2i.

8/(2+2i)
Multiply  by (2-2i)/(2-2i), which is equal to 1 but helps us rewrite and simplify the terms:
8(2-2i)/((2+2i)(2-2i))
8(2-2i) / (4 -4i + 4i - 4i²) Remember that i²=-1
8(2-2i)/ (4 - (-4))
8(2-2i) / (8)                    8 in the numerator and denominator cancel
= 2- 2i

Answer is 2 - 2i

Aand b are correctly balanced reactions. they have the same number of atoms in both sides of the reaction