Aline passes through point (3, 7) and has a slope of . the equation of the line is . if point a(x, 5) lies on the line, the value of x is . nextreset

(a) y = 3/4*x + 19/4

(b) x = 1/3

Step-by-step explanation:

Assumption: line slope (m) is 3/4  

(a)

Line general formula is y = m*x + b. In this exercise, you knew a point which lies on the line and its slope. So, replacing in the formula and solving for b gives

7 = 3/4*3 + b

b = 7 - 9/4

b = 19/4

Then, the equation of the line is y = 3/4*x + 19/4

(b)

Replacing the point into the formula obtained previously and solving for x gives

5 = 3/4*x + 19/4

x = (5 - 19/4)*4/3

x = 1/3

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right