What substitution should be used to rewrite 16(x3 + 1)2 – 22(x3 + 1) – 3 = 0 as a quadratic equation?

Notice you have the square of x^3 + 1 in the first term, and x^3 + 1 in the second term. think of x^3 + 1 as just a variable, such as u.let u = x^3 + 1.now when you write the equation in terms of u, it is a quadratic equation in u.16u^2 - 22u - 3 = 0answer: let u = x^3 + 1

B. u = (x^3 + 1)  i hope this works i got it from my note spiral

You need to include the original coordinates of the triangle to answer this. and how much does it translate (move left right up down)