Mathematics, 23.07.2019 20:10 chenepiernas

Find the equation for the line tangent to the parametric curve: xy==t3−25t25t2−t4 x=t3−25ty=25t2−t4 at the points where t=5t=5 and t=−5t=−5. for t=5t=5, the tangent line (in form y=mx+by=mx+b) is

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Find the equation for the line tangent to the parametric curve: xy==t3−25t25t2−t4 x=t3−25ty=25t2−t4...