Write the equation of a line that is parallel to y=0.6x+3y, and that passes through the point(−3,−5)

It is y=0.6x-3.2

Step-by-step explanation:

A line parallel to y = 0.6x + 3 will be of the form:

y = 0.6x + k

where k is a constant.  It passes through (-3,-5)

That being so,

y = 0.6x + k

-5 = 0.6 * (-3) + k

-5 = -1.8 + k

k = -5 + 1

k= -3.2

Therefore the answer is y = 0.6x - 3.2.

the ratios are reciprocals im positive

step-by-step explanation:

they are all positive numbers so it wouldn't be the other ones