Mathematics, 23.07.2019 09:40 smithsavannah295
If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation hequals=minus−16t squaredt2plus+vtplus+s, where h is in feet. if the object is propelled from a height of 88 feet with an initial velocity of 6464 feet per second, its height h is given by the equation hequals=minus−16t squaredt2plus+6464tplus+88. after how many seconds is the height 3636 feet?
Answers: 1
Mathematics, 21.06.2019 18:40, thepantsgirl
Solve the equation below: (x+4)/6x=1/x a. x=2 b. x=0,2 c. x=-2 d. x=0,-2
Answers: 1
Mathematics, 21.06.2019 19:00, Brendah4962
Solve the equation using the zero-product property. -3n(7n - 5) = 0 a. 0, -5/7 b. -1/3, -5/7 c. -1/3, 5/7 d. 0, 5/7
Answers: 2
Mathematics, 21.06.2019 19:20, hahah265
Suppose that a households monthly water bill (in dollars) is a linear function of the amount of water the household uses (in hundreds of cubic feet, hcf). when graphed, the function gives a line with slope of 1.65. if the monthly cost for 13 hcf is $46.10 what is the monthly cost for 19 hcf?
Answers: 3
If an object is propelled upward from a height of s feet at an initial velocity of v feet per second...
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