Mathematics, 23.07.2019 01:10 danuwell
Find the equation of the circle that has a diameter with endpoint located at (-5,-3) and (-11,-3).
Answers: 1
![\bf \textit{equation of a circle}\\\\ (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 \qquad center~~(\stackrel{-8}{{{ h}}},\stackrel{-3}{{{ k}}})\qquad \qquad radius=\stackrel{3}{{{ r}}} \\\\\\\ [x-(-8)]^2+[y-(-3)]^2=3^2\implies (x+8)^2+(y+3)^2=9](/tpl/images/0121/6129/8c5d1.png)
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Find the equation of the circle that has a diameter with endpoint located at (-5,-3) and (-11,-3)....
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