How do you solve 2x²-x=3 by factoring

the value of x are -1 and  

Step-by-step explanation:

we need to find the factor of 2x²-x=3  

subtract both the sides by 3, in above expression

2x²- x - 3 = 3 - 3

2x²- x - 3 = 0

we can write  x as -3x + 2x

2x²- 3x +2x - 3 = 0

2x²+ 2x -3x - 3 = 0

take out the common terms,

2x(x+ 1) -3(x +1) = 0

(x+ 1)(2x-3) = 0

If x+ 1 =0

⇒ x = -1

If 2x - 3=0

⇒

Therefore, the value of x are -1 and  

6 on both sides and twelve on the top and the bottom

step-by-step explanation:

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.