Aquadratic equation is shown below: 16x2 − 8x + 1 = 0 part a: describe the solution(s) to the equation by just determining the radicand. show your work. (5 points) part b: solve 4x2 − 8x − 45 = 0 by using an appropriate method. show the steps of your work, and explain why you chose the method used. (5 points)

16x^2 − 8x + 1 = 0

Part A: 
b^2 - 4ac for ax^2 + bx + c

16x^2 − 8x + 1 = 0
so in this case,
a = 16,  b = -8, c = 1

b^2 - 4ac
=(-8)^2 - (4 * 16* 1)
= 64 - 64
= 0
because it's equal 0, answer is one solution

Part B:

4x^2 − 8x − 45 = 0
solve the equation by factoring  
= (2x - 9)(2x + 5)

set (2x - 9)(2x + 5) equal to 0 to solve for x
so
(2x - 9)(2x + 5) = 0
2x - 9 = 0
  x = 9/2
  x = 4.5

2x + 5 = 0
  x = -5/2
  x = -2.5
answer
x = -2.5 or x = 4.5

Hope it helps

The first one is correct