1. suppose that f(x) varies directly with x and f(x) = 160 when x = 5. what is f(x) when x = 0.5? a. 16 b. 32 c. 160 d. 180 2. suppose that h(x) varies inversely with x and h(x) = 50 when x = 0.25. what is h(x) when x = 2? a. 0.5 b. 6.25 c. 12.5 d. 24

Answer

A. 16

Explanation

We know that f(x) varies directly with x, so this is a problem involving proportions.

We know that when f(x) = 160 when x = 5 and f(x) = ? when x = 0.5; in other words:

Now, we can express our proportion as a fraction and solve for f(x):

We can conclude that when

Answer

B. 6.25

Explanation

Just like before, we have a problem involving proportions, but this time is an inverse proportion since h(x) varies inversely with x.

First, lets set up our proportion just like before. We know that when h(x) = 50 when x = 0.25 and h(x) = ? when x = 2; in other words:

Now we can express our proportion as a fraction:

But remember that we are dealing with an inverse proportion here, so before solving for h(x) we need to flip the second fraction:

We can conclude that when

a

step-by-step explanation:

u take $30 minus $24. the answer/original($30)