Which values from the given replacement set make up the solution set of the inequality? 2b–4≥2 ; {1,2,3,4} 1,2 3,4 1,2,3 2,3,4

3,4

Step-by-step explanation:

Plug in each number for "b" in the inequality

2(1) - 4 ≥ 2

2 - 4 ≥ 2

-2 ≥ 2

1 is not a solution because -2 is not greater than or equal to 2.

2(2) - 4 ≥ 2

4 - 4 ≥ 2

0 ≥ 2

2 is not a solution because 0 is not greater than or equal to 2.

2(3) - 4 ≥ 2

6 - 4 ≥ 2

2 ≥ 2

3 is a solution because 2 is equal to 2.

2(4) - 4 ≥ 2

8 - 4 ≥ 2

4 ≥ 2

4 is a solution because 4 is greater than 2.

{3, 4} is your answer

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.

5+2x=a

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