What is the solution of the system? use the elimination method. {−4x−2y=−12 {2x+4y=−12

Divide the first equation by 2 and add the result to the second equation. This will eliminate x.

... (-4x -2y)/2 + (2x +4y) = (-12)/2 +(-12)

... 3y = -18 . . . . . collect terms

... y = -6 . . . . . . . divide by 3

Substitute this into either equation to find x. Let's use the second equation, where the coefficient of x is positive.

... 2x +4(-6) = -12

... 2x = 12 . . . . . . . . add 24

... x = 6 . . . . . . . . . . divide by 2

The solution is (x, y) = (6, -6).

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: