7y + 4x = 3; (-4, -7) write the equation in slope intercept form of the line that is perpendicular to the graph of the equation and passes through the given point.

Step-by-step explanation:

we have the original line equation

clearing for y:

Now we have an equation of the form slope- intercept:

where m is the slope and b is the y-intercept.

thus, the slope of the original line is:

Now to find the new line, since it has to be perpendicular their slopes must satisfy the following:

where m is the slope of the original line, and m1 is the slope of the new line:

this is the slope of the new perpendicular line that passes trough the point (-4,-7), so now we use the point slope equation to find the equation of said line:

where we know , and from the point (-4,-7)

so we have:

and we clear for y to leave the equation in the slope intercept form:

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

the first one, all those points on the line just make a strait line.