The total bear population in a certain area is represented by the function p=120(1.016)t , where t is time in years. how would you rewrite this equation to identify the weekly growth rate of the population? how would you solve this equation.

1) function: P = 120 (1.0160)^t, t in years

2) weekly function

w = 52 * t = 52t

=> P(w) = 120 (1.016)^ (52w)

3) growth rate = d P(w) / dw

d P(w) / dw = 120 * 52 * [ 1.016 ^ (52w) ] = 6240 [(1.016) ^ (52w) ]

4) solution of the equation

Separate variables

d P(w) = [ 6240 (1.016) ^ (52w)] dw

integrate from w = 0 until w

P(w) - Po = 7599.84 e ^ (0.82514w)

P(w) = Po + 7599.84 e ^ (0.82514w)

Aquadratic function is one of the form f(x)=ax2 + bx + c l, where a,b, and c are numbers with are not equal to zero.