Solve plz as soon as possible i beg u 1.given: ∆abc, m∠c = 90° m∠abc = 30° al - ∠ bisector, lb = 18m find: cl 2.given: δавс, m∠acb = 90° cd ⊥ ab , m∠acd = 30° ad = 6 cm. find: bd 3. in the right △abc with m∠c = 90°, m∠a = 75°, and ab = 12 cm. find the area of △abc.

Part A:

Given : ∆ABC, m∠C = 90° m∠ABC = 30°

This meanc that m∠BAC = 60°

Given that AL is an ∠ bisector, this means that m∠CAL = 30° and m∠CLA = 60°

Given that LB = 18m, then:


and


From (1) and (2):



Part B:

Given: ΔАВС, m∠ACB = 90°; CD⊥AB; m∠ACD = 30° and AD = 6 cm.

Then:



Given that m∠ACB = 90° and m∠ACD = 30°, then m∠BCD = 60°

Thus:



Part C:

Given △ABC with m∠C = 90°, m∠A = 75°, and AB = 12 cm.

Thus:



The area of △ABC is given by:

Ithink it’s b because it say 3 plastic rings and all the balls