How long must a simple pendulum be if it is to make exactly one swing per three seconds? (that is, one complete oscillation takes exactly 6.0

This is a physics question.

Use the formula for simple pendulum:

T = 2π √(L/g)

Where T is the period (time to complete a full oscilation), L is the lenght and g acceleration of gravity ≈ 9.81 m/s^2 .

So, solve for l:

√(L/g) = T / (2π)

L = [T / (2π) ] ^2 * g = [ 6.0s / (2π) ]^2 * 9.81 m/s^2 = 8.9 m

8.9 m

0=6x+2y+10 is equivalent to the simplified form: y= -3x - 5• parallel lines always have the same slope, different y intercept knowing this, we can say the slope, or m of the line parallel to y= -3x - 5 is -3.m= -3 hope this could !

The correct answer is addition