Also explain how to solve this. 20 points the developer name the streets if the entrance street is y = 2/3 x -7, by using these patterns. all the streets that run parallel to the entrance street (oak street) were given tree names, while all those that run perpendicular to the entrance street were given flower names. if it is neither parallel nor perpendicular to the main street, then the street was labeled with an animal name. street equation: y = -3/2x - 2 a.) weeping willow street b.) hibiscus street c.) oak street d.) panther street

B.) Hibiscus Street 

The key thing to remember is the slope of the lines. The equation for a line in slope intercept form is
y = ax + b
where
a = slope
b = y intercept

So the equation for Oak Street is y = 2/3x - 7. So it's slope is 2/3. And any street that has the same slope will be given a tree name. And any street that's perpendicular will be given a flower name. You can determine is a line is perpendicular if it has a slope that's the negative reciprocal. So a street that's perpendicular to Oak street will have a slope of -3/2.

Now you've just been given the equation to a new street that's y = -3/2x - 2. Since the slope is -3/2 and Oak street has a slope of 2/3, the new street is perpendicular to Oak street. And given the naming scheme, that means that the new street will have the name of a flower. So let's look at the available street names and pick a flower.

A.) Weeping Willow Street
* Nope a Weeping Willow is a tree. So this name won't work.
 
B.) Hibiscus Street 
* Yes. A Hibiscus is a flower, so this name is suitable.

C.) Oak Street 
* Nope. Not only is this a tree instead of a flower, but there's already an Oak street. So bad choice.

D.) Panther Street
* Nope, this is an animal, not a flower. Bad choice.

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.