Which of the following show the factored equivalent of f(x) = (x2 - 81)(x + 5) and its zeroes. f(x) = (x - 6)(x + 6)(x + 5); x= 6, -6, -5 f(x) = (x - 9)(x + 9)(x + 5); x= 9, -9, -5 f(x) = (x - 9)(x + 9)(x + 5); x= -9, -9, -5 f(x) = (x - 6)(x + 6)(x + 5); x= -6, 6, -5

Option B

Step-by-step explanation:

We have to write the function f(x) in the factored form.

f(x) = ( x² - 81 ) ( x+5 )

Since [ a² - b² = ( a-b ) ( a+b) ]

so f(x) = ( x² - 9² ) ( x + 5 )

=  ( x - 9 ) ( x + 9 ) ( x + 5 )

If these factors are the zero factors then

( x - 9 ) = 0 ⇒ x = 9

( x + 9 ) = 0 ⇒ x = -9

x + 5 = 0 ⇒ x = -5

Option B will be the answer.

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

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step-by-step explanation:

just for that im not answering