Three multiplied by the sum of 4 and a number is the same as 18 more than the number. find the number. if n is " the number," which equation could be used to solve for the number? 3n+4=n+18 4 (3+n)=n+18 3 (4+n)=n+18

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo

none cuz there are no "following statements" regarding the question

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

im not sure what this means: mc011-7.jpg

step-by-step explanation: