What is the area of a triangle with vertices at (−2, 1) , (2, 1) , and (3, 4) ? enter your answer in the box. units²

The Answer is 6.

Step-by-step explanation:

Area of triangle = 1/2 [ x_{1} (y_{2} -y_{3} ) + x_{2} (y_{3} - y_{1})+x_{3}(y_{1}-y_{2})

As given the vertices at (−2, 1) , (2, 1) , and ​ (3, 4)  

put in the equation  above

we result with

= 1/2 [-2(1-4)+ 2 (4-1) + 3 ( 1-1) ]

solving  

= 1/2 [6 + 6]

therefore

= 1/2 [12]

=6

area of the triangle is 6 units².

c > -10.55

step-by-step explanation:

p(x)= 8 x³ - 36 x² + 54 x - 27

q(x) = 2 x -3

you can check your mistake and then you can choose the correct option.

dividend =   8 x³ - 36 x² + 54 x - 27

divisor = 2 x -3

if you want to find quotient, proceed as follows

q(x)= 0

2 x - 3=0

x =

now , i have used division method , to find quotient and remainder