Factor the following polynomial 3y^2-13y+4

There is no GCF, so just factor it out: (3y−1)(y−4) OR you can have (y-4)(3y-1).

Okay multiply the coefficients of x² and the constant;
 
3×4=12 

How can we split -13 so that the numbers multiply to give 12?

-12×(-1)=12 and -12-1=-13 

Therefore, rewrite the equation; 

3y²-1y-12y+4
y(3y-1)-4(3y-1) <-- make sure everything inside the brackets remains the same
(y-4)(3y-1) 

Double check by expanding; 

(y-4)(3y-1)
3y²-1y-12²+4 
3y²-13y+4 <-- this is the same equation, meaning we were correct. 

Hope I helped :) 

6/9 i need more characters in my answer