The magnitudes and directions of two forces acting at a point p are given in (a) and (b). approximate the magnitude and direction of the resultant vector. (round your answers to the nearest whole number.) (a) 70 lb, n75°w (b) 60 lb, s5°e

For vector a:

Horizontal component = -70 cos 15 = -67.613
Vertical component = 70 sin 15 = 18.116

For vector b:

Horizontal component = 60 cos 85 = 5.232
Vertical component = -60 sin 85 = -59.772

For the resultant vector:

Horizontal component = -67.613 + 5.232 = -62.381
Vertical component = 18.116 - 59.772 = -41.656

Magnitude of the resultant vector is given by:



Direction of the resultant vector is given by:



Therefore, the magnitude of the resultant force is 75 lb and the direction of the resultant force is S56°W

(-0, -7) is your answer