Atextile fiber manufacturer is investigating a new drapery yarn, which the company claims has a mean thread elongation of 12 kilograms with a standard deviation of 0.5 kilograms. the company wishes to test the hypothesis upper h subscript 0 baseline colon mu equals 12 against upper h subscript 1 baseline colon mu less-than 12 using a random sample of n equals 4 specimens. calculate the p-value if the observed statistic is x overbar equals 11.25. round your final answer to five decimal places (e. g. 98.76543).

We solve this by using the z statistic, the formula for z score is:

z = (x – u) / s

where x is the sample value = 11.25, u is the mean = 12, and s is the standard deviation = 0.5

z = (11.25 – 12) / 0.5

z = -1.5

From the standard probability tables, the p value is:

P = 0.06680

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

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y

=

−

2

find the upper bound of the range.

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y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation:

i use my brain for prombles like this maybe you could try it

step-by-step explanation: