Mrs. trout estimated her math class next year would include 28 students. the actual size of the class turned out to be 32 students. she calculated the percent error in the following way.

If Mrs. Trout estimated that her math class next year would be 28 students but actually received 32 students;  to find the percentage of the difference of her estimation versus how many actual students there were, we would need to find the increased percentage.

Your answer would be that there was a 14.3% increase of students than what Mrs. Trout actually estimated in her class.

To find this:

Find the difference between the NEW number (32) and the ORIGINAL number (28).

32-28= 4

Next, divide the difference (4) by the ORIGINAL number (28).

4/28 = 0.14285

Lastly, you will multiply by 100.

0.14285 x 100 = 14.285% and rounded would give you 14.3%

Sample Response:Mrs. Trout set up the ratio correctly, but she forgot to multiply by 100 to get the correct percent.

answer: y = 3/2 x - 3

y = 1/8 x - 3/4 that would be your correct option

step-by-step explanation: w

answer: - (a)

(b) 88 seats

step-by-step explanation:

given: in an auditorium, there are 22 seats in the first row and 28 seats in the second row.

thus first term=

second term=

the number of seats in a row continues to increase by 6 with each additional row.

⇒d= 6

a) given formula :

b)   let the number of seats (n) = 12

substitute n=12 in the explicit rule formed in (a)

∴there are 88 seats in 12 rows.