In a right triangle, he measure of one acute angle is 3 times the sum of the other acute angle and 8, find the measure of angle 1 and 2

The measure of angles 1 and 2 are 16.5 and 73.5 respectively.

The sum of the two acute angles is complementary.

Let the complementary acute angles be x and y

Since they form a right angle triangle, hence;

x  + y = 90 1

If the measure of one acute angle is 3 times the sum of the other acute angle and 8, this is expressed as x = 3(y + 8)

Substitute the value of x into the equation 1 as shown:

3(y+8) + y = 90

3y + 24 + y = 90

4y + 24 = 90

4y = 90 - 24

4y = 66

y = 66/4

y = 16.5

Get the other acute angle:

x = 90 - y

x = 90 - 16.5

x = 73.5 degrees

Hence the measure of angles 1 and 2 are 16.5 and 73.5 respectively.

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step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3