The use of the normal probability distribution as an approximation of the sampling distribution of p̄ is based on the condition that both np and n(1 – p) equal or exceed a. 05 b. 5 c. 15 d. 30

Actually the proportion of every possible sample proportions is roughly normally
distributed with the mean "μ denoted with p" = p and standard deviation "σ denoted with p" = √(pq ÷ n) if and only if (np ≥ 5 and n(1-p) ≥ 5).

 

b. 5

 

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)