Aship leaves port at 1: 00 p. m. and travels s35°e at the rate of 26 mi/hr. another ship leaves the same port at 1: 30 p. m. and travels s20°w at 20 mi/hr. approximately how far apart are the ships at 3: 00 p. m.?

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

360/29

step-by-step explanation: