The volume that is inside the larger cylinder shown but outside the cylinder with the smaller radius, r, can be found with the formula below.
V= 1,024π−16πr2
V is the volume inside the larger cylinder but outside the smaller cylinder in cubic centimeters. r is the radius of the smaller cylinder in centimeters.
Which equation and solution give the radius of the smaller cylinder if the volume inside the larger cylinder but outside the smaller cylinder is 768π centimeters3?

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

3 is greater then both of those numbers