If the measure of one angle in a supplementary pair is double the other angle, find the measure of larger angle.

In a parallelogram sum of the adjacent angles

equals supplementary.

opposite angles are equal.

Let the smaller angle = x°

larger angle = twice the smaller angle - 30°

=2x° - 30°

x° +2 x° - 30 = 180°

3x° = 180 + 30

3x = 210

x = 210 / 3

x = 70°

Therefore,

smaller angle = x = 70°

larger angle = 2x - 30

= 2 × 70 - 30

= 140 - 30

= 110°

Required parallelogram angles are 70° , 110° ,

70° , 110°

I hope this helps you.