At the movie theatre, child admission is $5.10 and adult admission is $9.00 . on monday, 163 tickets were sold for a total sales of $1088.70 . how many adult tickets were sold that day?

a = adult tickets

c = child

c + a = 163 tickets total

rewrite as c = 163-a

5.10c + 9.00a = 1088.70

5.10(163-a) + 9.00a = 1088.70

831.30-5.10a + 9.00a = 1088.70

831.30 +3.9a = 1088.70

3.9a = 1088.70-831.30

3.9a  = 257.40

a = 257.40 / 3.9 = 66

 66 adult tickets were sold

answer: no

step-by-step explanation:

you are only given the cost not the amount of pounds.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!