What is the equation in point-slope form of the line passing through (2, 5) and (−1, 8)? y + 5 = 1(x + 2) y + 8 = −1(x − 1) y − 5 = −1(x − 2) y − 8 = 1(x − 2)

(2,5)(-1,8)slope formula : (y2 - y1) / (x2 - x1)
slope = (8 - 5) / (-1 - 2) = 3/-3 = -1

y - y1 = m(x - x1)
slope(m) = -1
(2,5)...x1 = 2 and y1 = 5
now we sub
y - 5 = -1(x - 2) <=== here is one solution

y - y1 = m(x - x1)
slope(m) = -1
(-1,8)...x1 = -1 and y1 = 8
sub
y - 8 = -1(x - (-1) =
y - 8 = -1(x + 1) <=== here is another one...but it is not an answer choice

so ur answer is : y - 5 = -1(x - 2)