Alocal civic group is selling t-shirts to raise funds for relay to life. they plan to sell 2500 t-shirts for $10. they consider raising the t-shirt price in order to earn more profit. for each $1 increase, they will sell 100 fewer t-shirts. let x represent the number of $1 increases. a. write a function, write a function, c(x), to represent the cost of one t-shirt based on the number of increases. b. write a function, t(x), to represent the number of t-shirts sold based on the number of increases. c. write a revenue function, r(x), for the t-shirt sell that could be used to maximize

a. Let us say that c(x) is the cost of one t shirt based on the number of increases therefore:

c = 10 + x

b. Say that t(x) is the number of t shirts sold based on the number of increases so:

 t = 2500 – 100 x

b. The revenue is simply the product:

r(x) = (10 + x) (2500 – 100 x)

Combining:

r(x) = 25000 – 1000 x + 2500 x – 100 x^2

r(x) = 25000 + 1500 x – 100 x^2

Taking the 1st derivative and setting dr / dx = 0 to get the maxima:

dr / dx = 1500 – 200 x

1500 = 200 x

x = 7.5

t = 2500 – 100 x = 2500 – 100 (7.5) = 1750

Hence 1750 shirts should be sold.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

it is true

step-by-step explanation:

all the combinations add up i used   calculator