![f(x) = \sqrt[3]{2x - 1} \\f(14) = \sqrt[3]{2(14) - 1} \\f(14) = \sqrt[3]{28 - 1} \\f(14) = \sqrt[3]{27} \\f(14) = 3](/tpl/images/0760/8434/be8eb.png)
![f(x) = \sqrt[3]{2x - 1} \\f(-62) = \sqrt[3]{2(-62) - 1} \\f(-62) = \sqrt[3]{-124 - 1} \\f(-62) = \sqrt[3]{-125} \\f(-62) = -5](/tpl/images/0760/8434/3403f.png)
![f(x) = \sqrt[3]{2x - 1} \\f(20) = \sqrt[3]{2(20) - 1} \\f(20) = \sqrt[3]{40 - 1} \\f(20) = \sqrt[3]{39}](/tpl/images/0760/8434/20f50.png)
HELP HOW DO I SOLVE THE FOLLOWING? PLEASE HELP
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Mathematics, 16.09.2020 15:01 EnzoF17
HELP HOW DO I SOLVE THE FOLLOWING? PLEASE HELP
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