Mathematics, 19.08.2019 10:30 24lbriscoe

Community gym charges a $50 membership fee and a $55 monthly fee. workout gym charges a $200 membership fee and a $45 monthly fre. how many months will the total amount of money paid to both gyms be th same? what will the amount be?

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Answer from: tre9990

For the Community Gym:
Membership Charge = $50
Monthly fee = $55
So for the 1st month total charge = $(50 +55)
   = $105
For each month the member pays $55
So after the 2nd month total payment = $(105 + 55)
   = $160
After 3rd month total payment = $(160 + 55)
   = $215
After 4th month total payment = $(215 + 55)
   = $270
After 5th month total payment = $(270 + 55)
   = $325
After 6th month total payment = $(325 + 55)
   = $380
Now for the Workout Gym:
Membership Charge = $200
Monthly Charge = $45
So for the 1st month the member pays = $(200 + 45)
      = $245
For the 2nd month total payment = $( 245 +45)
      = $290
For the 3rd month total payment = $(290 + 45)
   = $335
For the 4th month total payment = $(335 + 45)
   = $ 380
So the 6th month payment in the Community Gym is the same as the 4th month payment in the Workout Gym. The amount will be $380.

Answer from: Quest

if you mean

$(x - 8)(3x + 7)$

then it's c. 8, -7/3

but if you mean

$( {x}^{2} - 8)(3x + 7)$

then it is

$x = 2 \sqrt{2} \: \: and \: \: x = - \frac{7}{3}$

Answer from: Quest

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

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Community gym charges a $50 membership fee and a $55 monthly fee. workout gym charges a $200 members...