Aglobe has a diameter of 18 in. what is the surface area of the globe to the nearest square inch?
a. 108 in2
c. 1,018 in2
b. 285 in2
d. 2,216 in2

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2