What are the roots of the quadratic equation 0 = 2x^2 + 12x –14? 2, 12, –14 –7, 1 –1, 7 1, 6, –7 can you explain what it is wanting or asking?

It is basically asking you to find where the equation crosses the d-axis. 2x^2 + 12x -14 = (x-1)(2x-14). x-1=0. x=1. 2x-14=0. 2x=14. x=7. The solution/roots/zeros would be 1 and 7

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)

I'm sure the answer is a