What is the 13th term of the following arithmetic sequence? 5, 9, 13, 17, a. 52 b. 53 c. 54 d. 55

It would be B. 53. just keep adding 4 to the new number until you hit the 13th term.

Let n represent the term
1st term = 1 x 4 + 1 = 4n + 1 = 5
2nd term = 2 x 4 + 1 = 4n + 1 = 9
3rd term = 3 x 4 + 1 = 4n + 1 = 13

therefore we can see all terms has in common is 4n + 1

so now let n be 13
13 x 4 + 1 = 53
so the answer is b

29. because you will divide each number of months by 12 to find the number of years. which would mean, 5, 12.5, 16, 45, 50, 72.5. which is crazy. anyhow, i think you find the median in the middle. and yea hope your test goes good