Mathematics, 10.07.2019 08:30 astigall6360
Convert the complex number from rectangular form to polar form. z = -14 + 8i
Answers: 1
![\bf \stackrel{a}{-14}+\stackrel{b}{8}i\quad \begin{cases} r[cos(\theta )+i~sin(\theta )]\\ ----------\\ r=\sqrt{a^2+b^2}\\ \theta =tan^{-1}\left( \frac{b}{a} \right) \end{cases} \\\\\\ r=\sqrt{(-14)^2+8^2}\implies r=\sqrt{260}\implies \boxed{r=2\sqrt{65}} \\\\\\ \theta =tan^{-1}\left( \frac{8}{-14} \right)\implies \theta \approx -29.74^o](/tpl/images/0072/5924/9a67e.png)
![\bf \begin{cases} r=2\sqrt{65}\\ \theta =150.26^o \end{cases}\implies 2\sqrt{65}[cos(150.26^o)+i~sin(150.26^o)]](/tpl/images/0072/5924/c7793.png)
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Convert the complex number from rectangular form to polar form. z = -14 + 8i...
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