An aquarium with a square base has no top. there is a metal frame. glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. the volume is to be 20 m^3. express the total cost c in terms of the height h in meters. (hint: work out the cost of the glass and frame separately.)

Let x = one of the side lengths of the base.
Then area of the base = x². So volume of the base = x²h.
That gives us x²h = 20. Solving for x, we get x = √(20/h²).

Glass is needed to cover the sides of the aquarium. There are 4 sides and 1 base. Area of a side = hx = h√(20/h²). Area of the base = x² = 20/h. Total area of glass = h√(20/h²) + 20/h. So the cost for glass = 8 * [h√(20/h²) + 20/h] = 8 h√(20/h²) + 160/h.

Metal frame is needed along the edges of the sides. There are 4 edges on the top, 4 edges in the bottom and 4 vertical edges. So the total length of metal frame = 4x + 4x + 4h = 8 √(20/h²) + 4h. Then the cost for metal frame = 7 * [8 √(20/h²) + 4h] = 56 √(20/h²) + 28h.

So the total cost = 8 h√(20/h²) + 160/h +  56 √(20/h²) + 28h
   

Sorry i meant b in the other question