Can δtsr and δqrs be proven congruent by sas?

yes,   two triangles δtsr and δqrs be proven congruent by sas.

proof 1.→ in δ tsr and δqrs, if these are true

sr is common.

∠1 =∠2

and if , tr =rq

or

sr is common.

∠3=∠4

and if, ts =sq

then the two triangles can be proved congruent,by sas

→δtsr ≅ δqrs   [sas]

the co-ordinates of the transformed rectangle are:

d. (0, 0), (0, 3), (-3, 3), (-3, 0)

step-by-step explanation:

from the columns of the given matrix, the co-ordinates of the rectangle before transformation are:

(0, 0), (0, 3), (3, 3), (3, 0)

r =

transformed matrix can be obtained by multiplying the given matrix by r:

columns of the transformed matrix are:

0   0   -3   -3

0   3     3     0

from the columns of the resulted matrix, we can see that the vertices of the transformed triangle are:

(0, 0), (0, 3), (-3, 3), (-3, 0)

these sign is used to tell weather the number is greater or less than the number   <   or >     but this sign means its equal =    

hope this you and

step-by-step explanation: