According to the diagram, which statement is true? a) all rhombuses are squares. b) all squares are rhombuses. c) all rectangles are squares. d) all parallelograms are rectangles.

Its b. . . . . . . . . . . . . . . . . . . . . . . . . . . 

Your answer is B All squares are rhombuses because with a square if you turn it a certain direction it will make a rhombus also its not A because a rhombus is a different shape then a square its not C because rectangles are bigger than squares therefore rectangles are not squares so that takes out C when it came down to rather B, or D I choose B because parallelograms have sets of parallel lines like a triangle it has one set of parallel lines even though a rectangle has two sets it doesn't make it a parallelogram it makes it a quarduraltou.                                                                                                                                                     Your answer is B.

21 is the answer the answer is 21

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12