Aflag in the shape of a right triangle is hung over the side of a building as shown below. the total weight of the flag is 250 pounds and it has uniform density. a = 15 and b = 39.

(a) The density of flag is Pounds per square foot

(b) The weight of strip is Pounds

(c) The work is foot-pounds

(d) The exact work by roof is 1250 foot-pounds

Step-by-step explanation:

(a) We are given a flag in the shape of a right triangle.

The total weight of flag is 250 pounds and Uniform density.

Base of the flag

Area of the flag

Weight of flag = 250 pounds

Hence, The density of flag is

(b) Weight of strip which is h feet below the roof.

Length of strip

Width of strip

Weight = Density x area

Hence, The weight of strip is

(c) Work slice to move h feet above to the roof

work

Hence, The work is foot-pounds

(d) Exact work on the roof by hanging flag

Hence, The exact work by roof is 1250 foot-pounds

answer:     true

step-by-step explanation:

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

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