Plz the point (2, 4) is on the graph of f(x) = x^2. what is the value of b if the point (0.5, 4) is on the graph of f(bx)? 4 0.5 1 2.5

We know that (0.5, 4) is not on the graph of x^2 because when x = 0.5, f(x) = 0.25. 
Since our function is now f(bx), and we know that x = 0.5, then we need to multiply 0.5 by something so that (b * 0.5)^2 = 4 
We can now solve for b 
(b * 0.5)^2 = 4 
take the square root of both sides of the equal sign 
√(b * 0.5)^2 = √4 
b * 0.5 = 2 
divide both sides of the equal sign by 0.5 
b * 0.5 / 0.5 = 2/0.5 
b = 4 

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Aand b is what i think

Ithink the answer is b