Can someone show me step by step how to do these problems

23)

2(5-3x)<x-4(3-x)

distribute 2 to 5 then 2 to 3x and get 10 - 6x then go on the right side and distribute the -4 to the 3 = -12 cancel out both x since one is negative and ones positive. which is 10 - 6x < -12 

subtract 10 on each side and divide by 2

10-10= 0    -12 - 10= 22 divide by 2 is 11 x=11 do that with the other one also

add 5 subtract 1

step-by-step explanation:

you need to add a picture