By graphing the system of constraints, find the values of x and y that maximize the objective function. 2< _x< _6 1< _y< _5 x+y< _8 maximum for p=3x+2y answers: a. (2,1) b. (6,2) c. (2,5) d. (3,5)

First, we'd need to find the feasible region which is bounded by the constraints 2 ≤ x ≤ 6, 1 ≤ y ≤ 5 and x + y ≤ 8. Let's graph all of them and we'll get the feasible region as unshaded in the attached image. To find the maximum for p = 3x + 2y, we'll plug the coordinates of the vertices in and compare them. 
p(6,1) = 3(6) + 2(1) = 20
p(2,1) = 3(2) + 2(1) = 8
p(2,5) = 3(2) + 2(5) = 16
p(3,5) = 3(3) + 2(5) = 19
p(6,2) = 3(6) + 2(2) = 22
So the maximum value of p is 22 as x = 6 and y = 2.